If cosec - - 2- find the value of cot -sin -1-cos -2-

Ans. Cosecθ = 2 By applying pythagoras theorem, we will get cotθ = √(3) sinθ = 1/2 cosθ =√(3)/2 cot θ+sin θ/1+cos θ 2 √(3) + nbsp;1/2 nbsp; / 1+ nbsp;√(3) ...

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Standard XIII

Mathematics

Sign of Trigonometric Ratios in Different Quadrants

If cosec θ = ...

Question

If cosec θ = 2, find the value of (cot θ+ $\frac{s i n θ}{1 + c o s θ}$ -2.

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Solution

Ans. Cosecθ = 2
By applying pythagoras theorem, we will get
cotθ = $\sqrt{3}$
sinθ = $\frac{1}{2}$
cosθ = $\frac{\sqrt{3}}{2}$
cot θ+ $\frac{s i n θ}{1 + c o s θ}$ -2
$\sqrt{3}$ + $\frac{1}{2}$ / 1+ $\sqrt{3}$ /2 -2
2 $\sqrt{3}$ +3+1-4-2 $\sqrt{3}$ / 2+ $\sqrt{3}$
=0

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If cosec θ = 2, find the value of (cot θ+sinθ1+cosθ-2.

Ans. Cosecθ = 2 By applying pythagoras theorem, we will get cotθ = √3 sinθ = 12 cosθ =√32 cot θ+sinθ1+cosθ-2 √3 + 12 / 1+ √3/2 -2 2√3 +3+1-4-2√3/ 2+√3 =0

If cosec θ = 2, find the value of (cot θ+ $\frac{s i n θ}{1 + c o s θ}$ -2.

Ans. Cosecθ = 2
By applying pythagoras theorem, we will get
cotθ = $\sqrt{3}$
sinθ = $\frac{1}{2}$
cosθ = $\frac{\sqrt{3}}{2}$
cot θ+ $\frac{s i n θ}{1 + c o s θ}$ -2
$\sqrt{3}$ + $\frac{1}{2}$ / 1+ $\sqrt{3}$ /2 -2
2 $\sqrt{3}$ +3+1-4-2 $\sqrt{3}$ / 2+ $\sqrt{3}$
=0