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Byju's Answer
Standard X
Mathematics
Relation between Trigonometric Ratios
If cosec θ ...
Question
If
c
o
s
e
c
θ
+
cot
θ
=
a
, then
cos
θ
=
a
2
−
1
a
2
+
1
Open in App
Solution
For
a
=
c
o
s
e
c
θ
+
cot
θ
then
a
2
−
1
a
2
+
1
=
(
c
o
s
e
c
θ
+
cot
θ
)
2
−
1
(
c
o
s
e
c
θ
+
cot
θ
)
2
+
1
=
(
c
o
s
e
c
2
θ
+
2.
c
o
s
e
c
θ
.
cot
θ
+
cot
2
θ
)
−
1
(
c
o
s
e
c
2
θ
+
2
c
o
s
e
c
θ
.
cot
θ
+
cot
2
θ
)
+
1
=
(
2.
c
o
s
e
c
θ
.
cot
θ
+
2
cot
2
θ
)
(
2
c
o
s
e
c
2
θ
+
2
c
o
s
e
c
θ
.
cot
θ
)
[ Since
c
o
s
e
c
2
θ
−
1
=
cot
2
θ
and
cot
2
θ
+
1
=
c
o
s
e
c
2
θ
.]
=
cot
θ
(
c
o
s
e
c
θ
+
cot
θ
)
c
o
s
e
c
θ
(
c
o
s
e
c
θ
+
cot
θ
)
=
cot
θ
c
o
s
e
c
θ
=
cos
θ
.
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0
Similar questions
Q.
If
cosec
θ
-
sin
θ
=
a
3
,
sec
θ
-
cos
θ
=
b
3
, then prove that
a
2
b
2
a
2
+
b
2
=
1
Q.
Prove:
cot
θ
−
cos
θ
cot
θ
+
cos
θ
=
cosec
θ
−
1
cosec
θ
+
1
Q.
If
t
a
n
2
θ
=
1
−
a
2
, prove that
s
e
c
θ
+
(
t
a
n
3
θ
×
c
o
s
e
c
θ
)
=
(
2
−
a
2
)
3
2
.
Q.
If
cos
θ
−
sin
θ
=
m
,
sec
θ
−
cos
θ
=
n
eliminate
θ
.
If
cos
θ
−
sin
θ
=
a
3
, then
a
2
b
2
(
a
2
+
b
2
)
=
1
.
Q.
If
cosec
θ
+
cot
θ
cosec
θ
−
cot
θ
=
81
49
, then find
cos
θ
+
sin
θ
sin
θ
−
cos
θ
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