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Question

If cosecθ+cotθ=112, then tanθ=


A

2122

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B

1516

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C

44117

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D

11744

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Solution

The correct option is C

44117


44117

We have:

cosecθ+cotθ=112....(1)

1cosecθ+cotθ=211

cosec2θcot2θcosecθ+cotθ=211

(cosecθ+cotθ)(cosecθcotθ)(cosecθ+cotθ)=211

cosec A -cot θ=211.....(2)

Subtracting (1)and (2):

2cotθ=112211

2cotθ=121422

2cotθ=11722

cotθ=11744

1tanθ=11744

tanθ=44117


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