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Question

If cosec θ=10, find the values of all T - ratios of θ

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Solution

Cosec theta = √10/1 = H/P

H = √10 , P = 1

By pythagoras theroem,

(H)² = (B)² + (P)²

(B)² = (H)²-(P)²

(B)² = (√10)² - (1)²

(B)² = 10-1 => 9

B = √9 = 3


Therefore,

Sinθ = P/H = 1/√10

Cosθ = B/H = 3/√10

Tanθ = P/B = 1/3

Cotθ = B/P = 3/1

Secθ = H/B = √10/3

Cosecθ = H/P = √10/1


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