If cosec θ=√10, find the values of all T - ratios of θ
Cosec theta = √10/1 = H/P
H = √10 , P = 1
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)²-(P)²
(B)² = (√10)² - (1)²
(B)² = 10-1 => 9
B = √9 = 3
Therefore,
Sinθ = P/H = 1/√10
Cosθ = B/H = 3/√10
Tanθ = P/B = 1/3
Cotθ = B/P = 3/1
Secθ = H/B = √10/3
Cosecθ = H/P = √10/1