If cosec2θ=secθ-33°, where 2θ is an acute angle, find the value of θ.
Evaluating the given expression:
cosec2θ=secθ-33°
⇒cosec2θ=cosec90°-(θ-33°)∵sec(A)=cosec(90°-A)
⇒ 2θ=(90°-(θ-33°))
⇒ 2θ=90°-θ+33°
⇒ 3θ=123°
⇒ θ=41°
Hence, the value of the given expression is 41°.