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Question

If cosec2θ=secθ-33°, where 2θ is an acute angle, find the value of θ.


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Solution

Evaluating the given expression:

cosec2θ=secθ-33°

cosec2θ=cosec90°-(θ-33°)sec(A)=cosec(90°-A)

2θ=(90°-(θ-33°))

2θ=90°-θ+33°

3θ=123°

θ=41°

Hence, the value of the given expression is 41°.


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