If cosecA=2 then obtain the value of cotA+sinA1+cosA
Find the required value:
Given cosecA=2
Now,
cotA+sinA1+cosA=cosAsinA+sinA1+cosA=cosA+sin2A1+cosAsinA......................(1)
cosecA=2⇒sinA=12∵sinA=1cosecAcosA=1-sin2A=1-14=32
Putting the value of cosA and sinA in equation (1) we get
cosA+sin2A1+cosAsinA=32+1221+3212=23+142+34=23+12+3=23+12-32+32-3[Rationalizing]=43-6+2-34-3=33-4
Hence, the value of cotA+sinA1+cosA is 33-4.
if cosecA =2 . then obtain value of cotA+ sinA/1+cosA