If -1n2-10 n-108-5-6- then minimum integral value of n will be

The correct option is A 3n^2 10n + 21.6/π lt; √(3) (n 5)^2 lt; √(3)π + 3.4 2.1 lt; n lt; 7.9 ∴ Minimum integral value of n = 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Inequalities of Integrals

If -1n2-10 n+...

Question

If $c o t^{- 1} (\frac{n^{2} - 10 n + \frac{108}{5}}{π}) > \frac{π}{6},$ then minimum integral value of n will be

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

{cot}^{- 1} (\frac{n^{2} - 10 n + 21.6}{π}) > \frac{π}{6}, n \in N,

n

{cot}^{- 1} (\frac{n^{2} - 10 n + 21.6}{π}) > \frac{π}{6}, n ϵ N

n

{cot}^{- 1} \frac{n^{2} - 10 n + 21.6}{π} > \frac{π}{6}, n \in N

n

c o t^{- 1} \frac{n}{π} > \frac{π}{6}, n ϵ N

{cot}^{- 1} \frac{n}{π} > \frac{π}{6}, n \in N

Join BYJU'S Learning Program