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Question

If cot1(1+sinx+1sinx1+sinx1sinx)=xm,x(0,π4).Find m

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Solution

0<x<(π4)hence0<(x2)<(π8)andsosin(x2)<cos(x2)1+sinx=sin2(x2)+cos2(x2)+2sin(x2)cos(x2)=sin(x2)+cos(x2)and1sinx=cos(x2)sin(x2)hencegivenexpressioninquestion=cot1[(sin(x2)+cos(x2)+cos(x2)sin(x2)sin(x2)+cos(x2)cos(x2)+sin(x2))]=cot1(cot(x2))=(x2)hencem=2


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