CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

If cot1x+cot1y+cot1z=π2, then x+y+z is equal to

A
1x+1y+1z
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
xyz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
xy+yz+zx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2(1x+1y+1z)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B xyz
cot1x+cot1y+cot1z=π2
(π2tan1x)=π2(tan1x)=πtan1{x+y+xxyz1(xy+yz+zx)}=πx+y+xxyz1(xy+yz+zx)=tanπ=0
x+y+z=xyz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon