If -1 x -tan -1 3 - 2 then x-

The correct option is B 3 We know, ^ 1 θ #160; +tan ^ 1 θ #160; =π #160; 2 #160;∴ ^ 1 x +tan ^ 1 3 =π #160; 2 ⇒ x=3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Applications of Cross Product

If -1 x +ta...

Question

If ${cot}^{- 1} x + {tan}^{- 1} 3 = \frac{π}{2}$ then $x =$

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

{tan}^{- 1} (2 x) + {tan}^{- 1} (3 x) = π / 4

x =

?

- \frac{π}{4} < x < \frac{π}{4}

1 + | tan x | + ∣ ∣ {tan}^{2} x ∣ ∣ + . . . + \infty = \frac{\sqrt{3} (\sqrt{3} + 1)}{2}

x

{tan}^{- 1} \frac{x - 1}{x - 2} + {tan}^{- 1} \frac{x + 1}{x + 2} = \frac{π}{4}

x =

\frac{d y}{d x} + \frac{3}{{cos}^{2} x} y = \frac{1}{{cos}^{2} x}, x \in (\frac{- π}{3}, \frac{π}{3}),

y (\frac{π}{4}) = \frac{4}{3}

y (- \frac{π}{4})

t a n^{- 1} \frac{x - 3}{x - 4} + t a n^{- 1} \frac{x + 3}{x + 4} = \frac{3}{4}

x

Join BYJU'S Learning Program