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Question

If cotθ=13, then write the value of 1-cos2θ2-sin2θ.

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Solution

We have,cotθ=13cotθ=cotπ3θ=π3Now,1-cos2θ2-sin2θ=1-cos2π32-sin2π3=1-1222-322=11-1421-34=3454=35

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