If 2 A - 3 - 0- find cos 3A-

The correct option is A 0 cot^2 A = 3 cot nbsp;A = √(3) cot nbsp;A = cot nbsp;30 A = 30^∘ Thus, cos nbsp;3A = cos nbsp;9 ...

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Range of Trigonometric Ratios from 0 to 90 Degrees

If 2 A - 3 ...

Question

If ${cot}^{2} A - 3 = 0$ , find $cos 3 A$ .

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{cot}^{2} A - 3 = 0

cos 3 A

4 {cos}^{2} A - 3 = 0

0^{\circ} \leq A \leq 90^{\circ}

c o s 3 A .

A = 30^{0}

\frac{{cos}^{3} A - cos 3 A}{cos A} + \frac{{sin}^{3} A + sin 3 A}{sin A} = 3

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} a {cot}^{- 1} (\frac{b + x}{4}), & \frac{- 2}{3} < x < 0 2, & x = 0 \frac{ln (1 - c x)}{x}, & 0 < x < \frac{2}{3} \end{matrix} .

f

x = 0,

b^{2} - 2 a + c^{6}

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