If 3 x -sin 45-cos 45-cos 60- and 0- x - 90- then x -A- 15-B- 30-C- 45-D- 60-

The correct option is A 15^∘ cot 3x = sin 45^∘cos 45^∘+cos 60^∘ =( 1/√(2) ) ( 1/√(2) )+1/2) cot 3x = cot 45^∘ Taking inverse on both sides we get, 3x = 45^∘ ...

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Byju's Answer

Standard IX

Mathematics

Values of Trigonometric Ratios

If 3 x =sin 4...

Question

If $c o t 3 x = s i n 45^{\circ} c o s 45^{\circ} + c o s 60^{\circ}$ and $0 < x \leq 90^{\circ}$ , then $x$ = __________________

$15^{\circ}$

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$30^{\circ}$

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$45^{\circ}$

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$60^{\circ}$

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Solution

The correct option is A
$15^{\circ}$

$c o t 3 x = s i n 45^{\circ} c o s 45^{\circ} + c o s 60^{\circ}$

= $(\frac{1}{\sqrt{2}}) (\frac{1}{\sqrt{2}}) + \frac{1}{2})$

$c o t 3 x = c o t 45^{\circ}$

Taking inverse on both sides we get,

$3 x = 45^{\circ}$ $x = 15^{\circ}$

Hence (A)

Suggest Corrections

Similar questions

Q. Let

T_{1} = \frac{sin 45^{\circ} - sin 30^{\circ} + cot 90^{\circ}}{cos 45^{\circ} + cos 60^{\circ}}

and

T_{2} = \frac{sec 45^{\circ} - tan 45^{\circ}}{c o s e c 45^{\circ} + cos 0^{\circ} + cot 90^{\circ}}

, then

If cos 2x = cos 60^o cos 30^o + sin 60^o sin 30^o then x is equal to

Q. If tan x = 3 cot x then x = ?
(a) 60°
(b) 45°
(c) 30°
(d) 15°

Q. If tan x = 3 cot x, then x = ?
(a) 45°
(b) 60°
(c) 30°
(d) 15°

Q. If cos

^{2} 45 - c o s^{2} 30 = x . c o s 45. s i n 45

then x is .......

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If cot 3x=sin 45∘cos 45∘+cos 60∘ and 0<x≤90∘ , then x= __________________

The correct option is A 15∘ cot 3x=sin 45∘cos 45∘+cos 60∘ =(1√2)(1√2)+12) cot 3x=cot 45∘ Taking inverse on both sides we get, 3x=45∘ x=15∘ Hence (A)

If $c o t 3 x = s i n 45^{\circ} c o s 45^{\circ} + c o s 60^{\circ}$ and $0 < x \leq 90^{\circ}$ , then $x$ = __________________

The correct option is A
$15^{\circ}$

$c o t 3 x = s i n 45^{\circ} c o s 45^{\circ} + c o s 60^{\circ}$

= $(\frac{1}{\sqrt{2}}) (\frac{1}{\sqrt{2}}) + \frac{1}{2})$

$c o t 3 x = c o t 45^{\circ}$

Taking inverse on both sides we get,

$3 x = 45^{\circ}$ $x = 15^{\circ}$

Hence (A)