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Question

If cot(α+β)=0, then sin(α+2β) can be

A
sinα
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B
sinβ
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C
cosα
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D
cosβ
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Solution

The correct option is A cosβ
cot(α+β)=0cos(α+β)=0sin(α+β)=1

Hence

sin(α+2β)=sin((α+β)+β)

=sin(α+β)cosβ+cos(α+β)sinβ

=1cosβ+0=cosβ

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