Question

If $\cot \Theta =1$; find the value of : $5{\tan }^2\Theta +2{\sin }^2\Theta -3$

Answer 1

$\cot \Theta =1$
$\cot \Theta =\cot 45$
$\Theta ={45}^{\circ }$
$5{\tan }^2\Theta +2{\sin }^2\Theta -3$
= $5{\tan }^{2}45+2{\sin }^{2}45-3$
= $5(1{)}^2+2(\frac{1}{\sqrt{2}}{)}^2-3$
= $5+1-3$
= $3$