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Question

If cotθ=13 then find the value of (1cos2θ2sin2θ)

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Solution

Given,
cotθ=13cotθ=cot60oθ=60o(1cos2θ2sin2θ)
Putting the value of θ we get,
=1cos260o2sin260o=1(12)22(32)2=114234=414834=3454=35.

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