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Question

If cotx=2, find the value of (2+2sinx)(1sinx)(1+cosx)(22cosx)

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Solution

cotx=2
=2(1+sinx)(1sinx)2(1cosx)(1+cosx)
=1sin2x1cos2x
=cos2xsin2x
=cot2x
=(2)2
=4

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