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Question

If cot(x)=2, then find the value of (2+2sinx)(1sinx)(1+cosx)(22cosx)

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Solution

(2+2sinx)(1sinx)(1+cos)(22cosx)
2(1+sinx)(1sinx)2(1+cos)(1cosx)
(1sin2x)(1cos2x)=cot2x=22=4

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