Question

$\mathrm{If}\cot A=\frac{4}{3}\mathrm{and}\left(A+B\right)=90°,\mathrm{then}\mathrm{what}\mathrm{is}\mathrm{the}\mathrm{value}\mathrm{of}\tan B?$

Answer 1

$$\begin{gathered} \mathrm{We}\mathrm{have}, \\ \cot A=\frac{4}{3} \\ \Rightarrow \cot \left(90°-B\right)=\frac{4}{3}\left(\mathrm{As},A+B=90°\right) \\ \therefore \tan B=\frac{4}{3} \end{gathered}$$