If cotA=7/8, find (1/sin A) (1/sinA)÷(1+cosA) (1-cosA).
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Solution
I think in the numerator it is (1+sin A)(1-sin A) because it is a common question with same value of cotA given in the question in manu text books and the answer of that question is below please reffer
(1+sinA)(1-sinA)/(1+cosA)(1-cosA) (a+b)(a-b)=a^2-b^2 so 1-sin^2(A)/1-cos^2(A) because 1-sin^2A=cos^2 A 1-cos^2A=sin^2A so