If -7 - 8- then tan 2- equals to-

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Complementary Trigonometric Ratios

If θ=7 / 8, t...

Question

If cotθ = ⁷/₈ , then tan²θ equals to:

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θ = \frac{7}{8}

t a n^{2} θ

{tan}^{2} θ = (1 - e^{2})

sec θ + {tan}^{3} θ cosec θ

θ \in (\frac{π}{4}, \frac{π}{2})

f (θ) = sec 2 θ - tan 2 θ

f (\frac{π}{4} - θ)

If the equation $t a n θ + t a n 2 θ + t a n θ t a n 2 θ = 1 t h e n θ$ is equal to

\frac{{tan}^{2} θ}{1 + sec θ} + 1

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