If ${C u}^{2 +} / C u$ electrode is diluted $100$ times, then the change in emf is:

increase of

59 m V

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decrease of

59 m V

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increase of

29.5 m V

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decrease of

29.5 m V

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Solution

The correct option is C decrease of $59 m V$
1) Decrease by

2) By the Nearnst equation at $25^{o} C$ , we have

3) $E_{c e l l} = E_{c e l l}^{o} - 0.05916 \frac{V}{z} \times l o g \frac{A_{o x}}{A_{r e d}}$

4) As $C u^{2 +}$ is reductant and its conc. is getting reduced by 100 times, so the log value will increase by the factor of 2. Also the value of z is 2.

5) Thus, the overall E will decrease by $59 m V$ .

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Similar questions

By how much will the potential of half cell cu+2/Cu change, if the solution is diluted to 100 times at 298 K?

(1) Increases by 59 mV

(2) Decreases by 59 mV

(3) Increases by 29.5 mv

(4) Decreases by 29.5 mV

C u^{2 +} / C u

298 K

C u^{2 +} / C u

C u^{2 +}

100

298 K ?

[\frac{2.303 R T}{F} = 0.06]

C u^{2 +} (0.1 M) / C u

100

298 K

Z n / Z n^{+ 2}

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