If CuSO 4 - 5H 2 O s - CuSO 4 - 3H 2 O s- 2H 2 O l K p -1-086- 10 -4 atm 2 at 25 o C The efflorescent nature of CuSO4- 5H2O can be noticed when vapour pressure of H2O in atmosphere is-

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Liquids in Liquids

If CuSO 4 ·...

Question

If ${C u S O}_{4} \cdot 5 H_{2} O (s) ⇌ {C u S O}_{4} \cdot {3 H}_{2} O (s) + {2 H}_{2} O (l) K_{p} = 1.086 \times 10^{- 4} {a t m}^{2} a t 25^{o} C$ The efflorescent nature of ${C u S O}_{4} \cdot {5 H}_{2} O$ can be noticed when vapour pressure of $H_{2} O$ in atmosphere is:

> 7.92 m m

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< 7.92 m m

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≷ 7.92 m m

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none of these

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Solution

The correct option is B $< 7.92 m m$
Efflorescent nature of $C u S O_{4} .5 H_{2} O$ means the loss of some water molecules so the compound can float on the surface rather than at bottom.

The pressure constant contains only the partial pressure of gas, the partial solid and liquid is taken unity.

So, $C u S O_{4} .5 H_{2} O (s) ⇋ C u S O_{4} .3 H_{2} O (S) + 2 H_{2} O (g)$
$K_{p} = (P_{H_{2} O})^{2}$
$(P_{H_{2} O})^{2} = 1.086 \times 10^{- 4} a t m^{2}$
$P_{H_{2} O} = 1.04 \times 10^{- 2} a t m$

Now, $1 a t m = 760 m m o f H g$
$P_{H_{2} O} = 7.92 m m o f H g$
So, for the reaction to proceed forward, the $P_{H_{2} O} < 7.92 m m o f H g$
Hence, the correct option is (B).

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Similar questions

If $C u S O_{4 (s)}$ . $5 H_{2} O_{(s)}$ $⇋$ $C u S o_{4}$ . $H_{2} O_{(s)}$ + $2 H_{2} O$ (g) $K_{p}$ = 1.0 x $10^{- 4}$ atm2 at $250^{\circ}$ . The efflorescent nature of CuSO4 . 5H2O can be noticed when vapour pressure of H2O in atmosphere is:

{C u S O}_{4^{.}} {5 H}_{2} O (s) ⇌ {C u S O}_{4^{.}} {3 H}_{2} O (s) + 2 H_{2} O (g)

K_{p} = 4 \times 10^{- 4} {a t m}^{2}

and vapour pressure of water is

22.4

torr at

298

K. Then find out relative humidity.

Q. Under what vapour pressure of moisture in atmospheric conditions

C u S O_{4} \cdot 5 H_{2} O

will be efflorescent if

C u S O_{4} \cdot 5 H_{2} O (s) ⇌ C u S O_{4} \cdot 3 H_{2} O + 2 H_{2} O (g); K_{p} = 62.73 {(m m)}^{2}

Which of the following are the products formed on heating $C u S O_{4} . 5 H_{2} O (s)$ ?

C u S O_{4}

\cdot

5 H_{2} O (s)

⇌

C u S O_{4} \cdot

H_{2} O (s)

2 H_{2} O (g)

;

K_{p}

= 4

\times 10^{- 4}

a t m^{2}

if the vapour pressure of water is 38 torr then percentage of relative humidity is: ( Assume all data at constant temperature)

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If CuSO4⋅5H2O(s)⇌CuSO4⋅3H2O (s)+2H2O (l)Kp=1.086×10−4atm2 at 25oC The efflorescent nature of CuSO4⋅ 5H2O can be noticed when vapour pressure of H2O in atmosphere is:

If ${C u S O}_{4} \cdot 5 H_{2} O (s) ⇌ {C u S O}_{4} \cdot {3 H}_{2} O (s) + {2 H}_{2} O (l) K_{p} = 1.086 \times 10^{- 4} {a t m}^{2} a t 25^{o} C$ The efflorescent nature of ${C u S O}_{4} \cdot {5 H}_{2} O$ can be noticed when vapour pressure of $H_{2} O$ in atmosphere is: