If D -0 and at least one of D 1- D 2- D 3 is not 0 - then according to Cramer-s rule- the system of linear equations will haveA- non trivial solutionB- trivial solutionC- no solutionD- infinite solution

The correct option is C no solutionBy Cramer's rule x =D_1/D, y = D_2/D, z =D_3/D. Given D equal to 0 and at least one of D_1, D_2, D_3 is not 0. Therefore by C ...

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Standard XII

Mathematics

Cramer's Rule

If D =0 and a...

Question

If D = 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0, then according to Cramer's rule, the system of linear equations will have

non trivial solution

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trivial solution

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no solution

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infinite solution

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Solution

The correct option is C no solution
By Cramer's rule $x = \frac{D_{1}}{D}, y = \frac{D_{2}}{D}, z = \frac{D_{3}}{D}$ . Given D equal to 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0. Therefore by Cramer's rule we have no possible solutions for this set of equations..

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If D = 0 and at least one of D1,D2,D3 is not 0, then according to Cramer's rule, the system of linear equations will have

The correct option is C no solutionBy Cramer's rule x=D1D,y=D2D,z=D3D. Given D equal to 0 and at least one of D1,D2,D3 is not 0. Therefore by Cramer's rule we have no possible solutions for this set of equations..

If D = 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0, then according to Cramer's rule, the system of linear equations will have

The correct option is C no solution
By Cramer's rule $x = \frac{D_{1}}{D}, y = \frac{D_{2}}{D}, z = \frac{D_{3}}{D}$ . Given D equal to 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0. Therefore by Cramer's rule we have no possible solutions for this set of equations..