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Question

If d1 & d2 are the longest and shortest distances of (7,2) from the curve whose equation is x2+y210x14y=51 then Geometric mean of d1 & d2 is?

A
11
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B
7
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C
2
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D
211
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Solution

The correct option is D 211
x2+y210x14y51=0 P(7,2)
Center (5,7) Radius = 55
Longer distance d1=(7+5)2+(72)2+55
=13+55
Short distance d2=1355
GM=(13+55)(1355)=169125
=44
=211

1239449_1141316_ans_c4ff917bdac84df5bc5358de50b552ae.jpg

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