CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
173
You visited us 173 times! Enjoying our articles? Unlock Full Access!
Question

If d1 & d2 are the longest and shortest distances of (7,2) from the curve whose equation is x2+y210x14y=51 then Geometric mean of d1 & d2 is?

A
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
211
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 211
x2+y210x14y51=0 P(7,2)
Center (5,7) Radius = 55
Longer distance d1=(7+5)2+(72)2+55
=13+55
Short distance d2=1355
GM=(13+55)(1355)=169125
=44
=211

1239449_1141316_ans_c4ff917bdac84df5bc5358de50b552ae.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Operations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon