If D and E are the mid-points of AB and AC of -ABC respectively- then which of the following are not true-DE - BC nbsp- nbsp-2 - DE - BC nbsp- nbsp-DE - 1-2 nbsp- BCDE - 2 - BC nbsp- nbsp-

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Diagonals of a Rhombus Are Perpendicular to Each Other

If D and E ar...

Question

If D and E are the mid-points of AB and AC of ΔABC respectively, then which of the following are not true?

∥

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2 × DE = BC

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DE = 2 × BC

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DE =

\frac{1}{2}

× BC

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Solution

The correct option is C DE = 2 × BC

According to the mid-point theorem: if D and E are the mid-points of the sides AB and AC respectively, then DE | | BC and DE = $\frac{1}{2}$ × BC ⇒ 2 × DE = BC.

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If D and E are the mid-points of AB and AC of ΔABC respectively, then which of the following are not true?

The correct option is C DE = 2 × BC According to the mid-point theorem: if D and E are the mid-points of the sides AB and AC respectively, then DE | | BC and DE = 12 × BC ⇒ 2 × DE = BC.

The correct option is C DE = 2 × BC

According to the mid-point theorem: if D and E are the mid-points of the sides AB and AC respectively, then DE | | BC and DE = $\frac{1}{2}$ × BC ⇒ 2 × DE = BC.