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Question

If D=∣ ∣11111+x1111+y∣ ∣ for x0,y0 then D is-

A
divisible by neither x nor y
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B
divisible by both x and y
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C
divisible by x but not y
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D
divisible by y but not x
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Solution

The correct option is C divisible by both x and y
D=∣ ∣11111+x1111+y∣ ∣
Applying C2C2C1;C3C3C1
=∣ ∣1001x010y∣ ∣=1(xy0)0+0=xy
Hence, D is divisible by both x and y

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