If D=∣∣
∣∣11111+x1111+y∣∣
∣∣ for x≠0,y≠0 then D is-
A
divisible by neither x nor y
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B
divisible by both x and y
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C
divisible by x but not y
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D
divisible by y but not x
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Solution
The correct option is C divisible by both x and y D=∣∣
∣∣11111+x1111+y∣∣
∣∣ Applying C2→C2−C1;C3→C3−C1 =∣∣
∣∣1001x010y∣∣
∣∣=1(xy−0)−0+0=xy Hence, D is divisible by both x and y