If D- E are the midpoints of A B- AC of - A B C- then B E- DC

The correct option is D 3/2BC O⃗D =O⃗A+O⃗B/2, O⃗E=O⃗A+O⃗C/2 B⃗E +D⃗C=O⃗E O⃗B +O⃗C O⃗D=O⃗A+O⃗C/2 O⃗B +O⃗C O⃗A+O⃗B/2 =O⃗A+O⃗C 2O⃗B+2O⃗C O⃗A O⃗B/2=3O⃗C 3O⃗B/2=3/ ...

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Byju's Answer

Standard XII

Physics

Rounding Off

If D, E are t...

Question

If D,E are the midpoints of AB, AC of $Δ A B C$ , then $- - \to B E + - - \to D C$

- - \to B C

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\frac{1}{2} - - \to B C

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2 - - \to B C

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\frac{3}{2} - - \to B C

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Solution

The correct option is D $\frac{3}{2} - - \to B C$

$\to O D = \frac{\to O A + \to O B}{2}, \to O E = \frac{\to O A + \to O C}{2} \to B E + \to D C = \to O E - \to O B + \to O C - \to O D = \frac{\to O A + \to O C}{2} - \to O B + \to O C - \frac{\to O A + \to O B}{2} = \frac{\to O A + \to O C - 2 \to O B + 2 \to O C - \to O A - \to O B}{2} = \frac{3 \to O C - 3 \to O B}{2} = \frac{3}{2} (\to O C - \to O B) = \frac{3}{2} \to B C .$

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If D,E are the midpoints of AB, AC of ΔABC, then −−→BE+−−→DC

The correct option is D 32−−→BC →OD=→OA+→OB2,→OE=→OA+→OC2→BE+→DC=→OE−→OB+→OC−→OD=→OA+→OC2−→OB+→OC−→OA+→OB2=→OA+→OC−2→OB+2→OC−→OA−→OB2=3→OC−3→OB2=32(→OC−→OB)=32→BC.

If D,E are the midpoints of AB, AC of $Δ A B C$ , then $- - \to B E + - - \to D C$