If D, E, F are the midpoints of sides BC, CA and AB of â–³ ABC, then the ratio of the area of â–³ DEF to â–³ ABC is:
1: 4
D, E, F are the midpoints of sides BC, CA and AB of △ABC ...(given)
Hence, DEAB=FEBC=FDAC=12 .... (SSS Similarity)
△ DEF∼△ ABC
area (Δ DEF)area (Δ ABC)=(DFAC)2=(12)2=14