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Relation between Radian and Degree

If D, G and R...

Question

If D, G and R denote respectively the number of degrees, grades and radians in an angle, then

A

$\frac{D}{100} = \frac{G}{90} = \frac{2 R}{π}$

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B

$\frac{D}{90} = \frac{G}{100} = \frac{R}{π}$

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C

$\frac{D}{90} = \frac{G}{100} = \frac{2 R}{π}$

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D

$\frac{D}{90} = \frac{G}{100} = \frac{R}{2 π}$

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Solution

The correct option is C
$\frac{D}{90} = \frac{G}{100} = \frac{2 R}{π}$

It is the relation between degree, grade and radian.

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Similar questions

Q. If D, G and R denote respectively the number of degrees, grades and radians in an angle, then
(a)

\frac{D}{100} = \frac{G}{90} = \frac{2 R}{π}

\frac{D}{90} = \frac{G}{100} = \frac{R}{π}

\frac{D}{100} = \frac{G}{100} = \frac{2 R}{π}

\frac{D}{90} = \frac{G}{100} = \frac{R}{2 π}

Q. The measure of an angle in degrees, grades and radians be D, G and C respectively, then relation between them

\frac{D}{90} = \frac{G}{100} = \frac{2 C}{π}

1^{\circ} = {(\frac{180}{π})}^{\circ} ≃ 57^{\circ}, 17^{'}, 44. 8^{''}

and sum of interior angles of a

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(2 n - 4) \frac{π}{2}

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Q. The measure of an angle in degrees, grades and radians be D, G and C respectively, then relation between them

\frac{D}{90} = \frac{G}{100} = \frac{2 C}{π}

1^{\circ} = {(\frac{180}{π})}^{\circ} ≃ 57^{\circ}, 17^{'}, 44. 8^{''}

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Q. The measure of an angle in degrees, grades and radians be D, G and C respectively, then relation between them

\frac{D}{90} = \frac{G}{100} = \frac{2 C}{π}

1^{\circ} = {(\frac{180}{π})}^{\circ} ≃ 57^{\circ}, 17^{'}, 44. 8^{''}

and sum of interior angles of a

n

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(2 n - 4) \frac{π}{2}

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Q. The measure of an angle in degrees, grades and radians be D, G and C respectively, then relation between them

\frac{D}{90} = \frac{G}{100} = \frac{2 C}{π}

1^{\circ} = {(\frac{180}{π})}^{\circ} ≃ 57^{\circ}, 17^{'}, 44. 8^{''}

and sum of interior angles of a

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