Question

If $d=\mathrm{HCF}(48,72)$ , find the value of $d$.

Answer 1

Calculate $\mathrm{HCF}$ of $48$ and $72$:

Given, $\mathrm{HCF}$ of $48$ and $72$ is $d$.

Prime factors of:

$$\begin{gathered} 48=2\times 2\times 2\times 2\times 3 \\ 72=2\times 2\times 2\times 3\times 3 \end{gathered}$$

So, the highest common factor of $48$ and $72$ is $d=2\times 2\times 2\times 3=24$.

Therefore, the value of $d$ is $24$.