Question

If d is the determinant of a square matrix A of order n, then the determinant of its adjoint is
(a) dⁿ
(b) dⁿ⁻¹
(c) dⁿ⁺¹
(d) d

Answer 1

(b) dⁿ⁻¹

We know,
$\left|\mathrm{adj}A\right|={\left|A\right|}^{n-1}$
$\Rightarrow \left|\mathrm{adj}A\right|=d^{n-1}$