Question

If d is the diagonal of the square, the area of the square is __ ${cm}^2$. (d = 8 cm).

Answer 1

$d^2=a^2+a^2\Rightarrow a=\frac{d}{\sqrt{2}}$

Therefore the area of the square is =$a^2=(\frac{d}{\sqrt{2}}{)}^2$ = $\frac{64}{2}$ = 32 $c{m}^2$The area of square is 32 $c{m}^2$.