If $D$ is the discriminant of $x^{2} + 4 x + 1 = 0$ , then the value of $D^{2}$ , is

100

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12

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144

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10

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Solution

The correct option is B $144$
$x^{2} + 4 x + 1 = 0$
$D = b^{2} - 4 a c$
$D = (4)^{2} - 4 (1) (1)$
$D = 16 - 4$
$D = 12$
$D^{2} = 12^{2} = 144$

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