If d is the HCF of 45 and 27, find x and y satisfying d=27x+45y

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Solution

hcf of 27 and 45 is 9
so d = 9
9 = 27x + 45y
9 = 9 (3x + 5y)
1 = 3x + 5y

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Similar questions

If d is the hcf of 45 and 27 , find the value of x and y satisfying d = 27x +45y give solutions step by step

d

H C F

45

27

x

d = 27 x - 45

if d is the H.C.F of 45 and 27, find x and y satisfying d= 27x +45y.

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