Question

If $D$ is the mid-point of the side $BC$ in $△ABC$ where $AB=AC$, then $\angle ADC$ is

• A. ${60}^{°}$
• B. ${45}^{°}$
• C. ${120}^{°}$
• D. ${90}^{°}$

Answer 1

The correct option is D

${90}^{°}$

Explanation for correct option:

Two sides of the triangle are equal, so, it is an isosceles triangle.

$D$ is the mid-point of $BC$, so, $AD$ is the median.

In isosceles triangle the median through common vertex $A$ of equal sides makes an angle of ${90}^{°}$ on the side $BC$.

Therefore, $\angle ADC={90}^{°}$.

Hence, the option D is the correct answer.