If $D \neq 0$ and at least one of $D_{1}, D_{2}, D_{3}$ is not 0 then according to Cramer's rule the system of linear equations will have

non trivial solution

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trivial solution

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infinite solutions

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no solutions

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Solution

The correct option is A
non trivial solution

By Cramer's rule
$x = \frac{D 1}{D}, y = \frac{D 2}{D}, z = \frac{D 3}{D}$ . Given $D$ not equal to 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0.
Therefore we have a non trivial solution.

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If $D \neq 0$ and at least one of $D_{1}, D_{2}, D_{3}$ is not 0 then according to Cramer's rule the system of linear equations will have

Q. If

D \neq 0

and at least one of

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is not 0 then according to Cramer's rule the system of linear equations will have

If $D = 0$ and at least one of $D_{1}, D_{2}, D_{3}$ is not 0 then according to Cramer's rule the system of linear equations will have

Q. If D = 0 and at least one of

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Which of the following cases will not lead to non trivial solutions in case of system of linear equations according to Cramer's rule Convention given D != 0 ?

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If D≠0 and at least one of D1,D2,D3 is not 0 then according to Cramer's rule the system of linear equations will have

The correct option is A non trivial solution By Cramer's rule x=D1D,y=D2D,z=D3D. Given D not equal to 0 and at least one of D1,D2,D3 is not 0. Therefore we have a non trivial solution.

If $D \neq 0$ and at least one of $D_{1}, D_{2}, D_{3}$ is not 0 then according to Cramer's rule the system of linear equations will have

The correct option is A
non trivial solution

By Cramer's rule
$x = \frac{D 1}{D}, y = \frac{D 2}{D}, z = \frac{D 3}{D}$ . Given $D$ not equal to 0 and at least one of $D_{1}, D_{2}, D_{3}$ is not 0.
Therefore we have a non trivial solution.