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Question

If Dp=∣∣ ∣ ∣∣p158p2359p32510∣∣ ∣ ∣∣, then D1+D2+D3+D4+D5 is equal to

A
0
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B
25
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C
625
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D
none of these
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Solution

The correct option is D none of these
Dp=∣ ∣ ∣p158p2359p32510∣ ∣ ∣=5∣ ∣ ∣p38p279p3510∣ ∣ ∣=5(p(7045)p2(3040)+p3(2756))=5(25p+10p229p3)
D1+D2+D3+D4+D5=5(25+1029)+5(25.2+10.2229.23)+5(25.3+10.3229.33)+5(25.4+10.4229.43)+5(25.5+10.5229.53)=28000

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