If Dp=∣∣
∣
∣∣p158p2359p32510∣∣
∣
∣∣, then D1+D2+D3+D4+D5 is equal to
A
0
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B
25
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C
625
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D
none of these
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Solution
The correct option is D none of these Dp=∣∣
∣
∣∣p158p2359p32510∣∣
∣
∣∣=5∣∣
∣
∣∣p38p279p3510∣∣
∣
∣∣=5(p(70−45)−p2(30−40)+p3(27−56))=5(25p+10p2−29p3) D1+D2+D3+D4+D5=5(25+10−29)+5(25.2+10.22−29.23)+5(25.3+10.32−29.33)+5(25.4+10.42−29.43)+5(25.5+10.52−29.53)=28000