If d1 and d2 are the densities of a liquid at t10C and t20C- then d1-d2 is - coefficient of real expansion

The correct option is C 1+γ t_21+γ t_1 Let the density of liquid at 0^∘C be d_0 . d_1=d_01+γ t_1 Also #160; d_2=d_01+γ t_2 d_1d_ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Reynold's Number

If d1 and d2 ...

Question

If d1 and d2 are the densities of a liquid at $t_{1}^{0} C$ and $t_{2}^{0} C$ , then $\frac{d_{1}}{d_{2}}$ is ( $γ$ = coefficient of real expansion)

\frac{1 + γ t_{1}}{1 + γ t_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1 - γ t_{1}}{1 - γ t_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1 + γ t_{2}}{1 + γ t_{1}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1 - γ t_{2}}{1 - γ t_{1}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1 + γ t_{2}}{1 + γ t_{1}}$
Let the density of liquid at $0^{\circ} C$ be $d_{0}$ .
$⟹ d_{1} = \frac{d_{0}}{1 + γ t_{1}}$
Also $d_{2} = \frac{d_{0}}{1 + γ t_{2}}$
$⟹ \frac{d_{1}}{d_{2}} = \frac{1 + γ t_{2}}{1 + γ t_{1}}$

Suggest Corrections

Similar questions

Q. If

α, β

γ

are the roots of the equation

x^{3} - x - 1 = 0

then the value of,

\frac{1 + α}{1 - α} + \frac{1 + β}{1 - β} + \frac{1 + γ}{1 - γ}

α, β

and

γ

are three angles given by

α = 2 {tan}^{- 1} (\sqrt{2} - 1), β = 3 {sin}^{- 1} \frac{1}{\sqrt{2}} + {sin}^{- 1} (- \frac{1}{2})

and

γ = {cos}^{- 1} \frac{1}{3} .

Then

One mole of an ideal gas with $\frac{C_{p}}{C_{v}} = γ$ at absolute temperature $T_{1}$ is adiabatically compressed from an initial pressure
$P_{1}$ to a final pressure $P_{2}$ . The resulting temperature $T_{2}$ of the gas is given by

At 0 $^{0}$ C the densities of a cork and a liquid in which the cork floats are $d_{1}$ and $d_{2}$ respectively. The coefficient of expansion for the material of the cork and the liquid are $γ$ and 100 $γ$ respectively. If the cork sinks when the temperature of the liquid is t $^{0}$ C then the ratio $\frac{d_{2}}{d_{1}}$

(1): when a liquid with a coefficient of $γ$ is heated in a vessel of a coefficient of linear expansion $\frac{γ}{3}$ , the level of liquid in the vessel remains unchanged.

(2): $γ_{a} = γ_{r} - γ_{g} = γ_{r} - 3 α = 0$

Join BYJU'S Learning Program

If d1 and d2 are the densities of a liquid at t01C and t02C, then d1d2 is (γ= coefficient of real expansion)

The correct option is C 1+γt21+γt1Let the density of liquid at 0∘C be d0.⟹d1=d01+γt1Also d2=d01+γt2⟹d1d2=1+γt21+γt1

If d1 and d2 are the densities of a liquid at $t_{1}^{0} C$ and $t_{2}^{0} C$ , then $\frac{d_{1}}{d_{2}}$ is ( $γ$ = coefficient of real expansion)

The correct option is C $\frac{1 + γ t_{2}}{1 + γ t_{1}}$
Let the density of liquid at $0^{\circ} C$ be $d_{0}$ .
$⟹ d_{1} = \frac{d_{0}}{1 + γ t_{1}}$
Also $d_{2} = \frac{d_{0}}{1 + γ t_{2}}$
$⟹ \frac{d_{1}}{d_{2}} = \frac{1 + γ t_{2}}{1 + γ t_{1}}$