If DB is the bisector of ∠ADC?, then which of the following options is/are correct?
A
∠ADB=∠BDC
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B
∠ADB+∠BDC=∠ADC
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C
∠ADC=2×∠ADB
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D
∠ADC=2×∠BDC
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Solution
The correct options are A∠ADB=∠BDC B∠ADB+∠BDC=∠ADC C∠ADC=2×∠ADB D∠ADC=2×∠BDC ∠ADB=∠BDC as BD is the angular bisector of∠ADC Let∠ADB=∠BDC=x∴∠ADC=∠ADB+∠BDC=2x⇒∠ADC=2x=2∠ADB=2∠BDC