Question

If ${\Delta }_0<P$, the correct electronic configuration for $d^4$ system will be:

• A. $t_{2g}^4{e}_g^0$
• B. $t_{2g}^3{e}_g^1$
• C. $t_{2g}^0{t}_g^4$
• D. $t_{2g}^2{e}_g^2$

Answer 1

Answer: (B)

$t_{2g}^3{e}_g^1$

On the basis of crystal field theory, for a $d^4$ ion, if ${\Delta }_0<P$ , then the complex is a high spin complex formed by the association of weak field ligands with the metal.

As a result the fourth electron enters one of the $e_g$ orbitals, there by exhibiting the electronic configuration : $t_{2g}^3{e}_g^1$