Question

If ${\Delta }_0<P$, the correct electronic confirguration for $d^4$ system will be:

• A. $t_{2g}^4{e}_g^0$
• B. $t_{2g}^3{e}_g^1$
• C. $t_{2g}^0{t}_g^4$
• D. $t_{2g}^2{e}_g^2$

Answer 1

Answer: (B)

$t_{2g}^3{e}_g^1$

If ${\Delta }_0$ (crystal field splitting energy of octahedral field) <P (pairing energy), that means the ligand is a weak field ligand which will lead to the formation of high spin complex . So, the electronic configuration of d+ system is $t_2^3$g eg${}^1$