If - 1 - x b b a x b a a x and - 2 - x b a x are the given determinants- then

The correct option is C d dx (Δ_ 1 )=3Δ_ 2 Given, nbsp; Δ nbsp; _ 1 = x amp; b amp; b a amp; x amp; b a amp; a amp ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of a Determinant

If Δ 1 = x ...

Question

If $Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x & b & b a & x & b a & a & x \end{matrix} ∣ ∣ ∣ ∣$ and $Δ_{2} = ∣ ∣ ∣ \begin{matrix} x & b a & x \end{matrix} ∣ ∣ ∣$ are the given determinants, then

Δ_{1} = 3 {(Δ_{2})}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{d}{d x} (Δ_{1}) = 3 Δ_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{d}{d x} (Δ_{1}) = 3 {(Δ_{2})}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ_{1} = 3 {Δ_{2}}^{3 / 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x & b & b a & x & b a & a & x \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ \begin{matrix} x & b a & x \end{matrix} ∣ ∣ ∣

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x & a & b b & x & a a & b & x \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ \begin{matrix} x & b a & x \end{matrix} ∣ ∣ ∣

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x a a \end{matrix} \begin{matrix} b x a \end{matrix} \begin{matrix} b b x \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ \begin{matrix} x & b a & x \end{matrix} ∣ ∣ ∣

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} x & b & b a & x & a a & a & x \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ \begin{matrix} x & b a & x \end{matrix} ∣ ∣ ∣

Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} a & b & c x & y & z p & q & r \end{matrix} ∣ ∣ ∣ ∣

Δ_{2} = ∣ ∣ ∣ ∣ \begin{matrix} y & b & q x & a & p z & c & r \end{matrix} ∣ ∣ ∣ ∣

Δ_{1}

Join BYJU'S Learning Program