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Question

If Δ1=∣ ∣xsinθcosθsinθx1 cosθ1x∣ ∣ and Δ2=∣ ∣xsin2θcos2θsin2θx1 cos2θ1x∣ ∣ , x0 ; then for all θ(0,π2) :

A
Δ1Δ2=2x3
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B
Δ1+Δ2=2x3
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C
Δ1+Δ2=2(x3+x1)
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D
Δ1Δ2=x(cos2θcos4θ)
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