If Δ1=∣∣
∣∣10202−10−13∣∣
∣∣ and Δ2=∣∣
∣∣2−10310002∣∣
∣∣, then the value of Δ1Δ2 is
A
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
−50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C50 GivenΔ1=∣∣
∣∣10202−10−13∣∣
∣∣,Δ2=∣∣
∣∣2−10310002∣∣
∣∣ ⇒Δ1Δ2=∣∣
∣∣2+0+0−1+0+00+0+40+6+00+2+00+0−20−3+00−1+00−0+6∣∣
∣∣
So, Δ1Δ2=∣∣
∣∣2−1462−2−3−16∣∣
∣∣
Expanding along R1,