If ΔABC and ΔBDE are equilateral triangles, where D is the mid point of BC, find the ratio of areas of ΔABC and ΔBDE
Given: In ΔABC and ΔBDE are equilateral triangles. D is the midpoint of BC.
To find:
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Since D is the midpoint of BC, BD : DC = 1.
We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.
Let DC = x, and BD = x
Therefore BC = BD + DC = 2x
Hence
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