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Question

If ΔABCΔDEF, AB = 4cm, DE = 6, EF = 9cm and FD = 12cm, then find the perimeter of ΔABC.

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Solution

Given, AB = 4cm, DE = 6cm, and EF 9cm and FD = 12cm
Also ΔABCΔDEF
ABED=BCEF=ACDF
46=BC9=AC12
On taking first two terms, we get
46=BC9
BC=4×96=6 cm
=AC=6×129=8 cm
Now, perimeter of ΔABC=AB+BC+AC
=4+6+8=18 cm

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