Ratio of Areas of Triangles Having Common Vertex and Bases in a Straight Line
If Δ ABC ∼Δ D...
Question
If ΔABC∼ΔDEF, AB = 4cm, DE = 6, EF = 9cm and FD = 12cm, then find the perimeter of ΔABC.
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Solution
Given, AB = 4cm, DE = 6cm, and EF 9cm and FD = 12cm Also ΔABC∼ΔDEF ∴ABED=BCEF=ACDF ⇒46=BC9=AC12 On taking first two terms, we get 46=BC9 ⇒BC=4×96=6cm =AC=6×129=8cm Now, perimeter of ΔABC=AB+BC+AC =4+6+8=18cm