If - ABC - DEF such that area of - ABC is 9 cm2 and the area of - DEF is 16 cm2 and BC - 2-1 cm- Find the length of EF- -2 MARKS-

Concept: 1 Mark Application: 1 Marks We have , Δ ABC ∼Δ DEF ⇒area (Δ ABC)/area (Δ DEF) = BC^2/EF^2 ⇒9/16 = (2.1)^2/EF^2 ⇒3/4 = 2.1/EF ⇒ EF = 4 × 2.1/3 ...

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Standard VIII

Mathematics

Area of Square & Rectangle

If Δ ABC ∼Δ D...

Question

If $Δ A B C \sim Δ D E F$ such that area of $Δ A B C$ is $9 c m^{2}$ and the area of $Δ D E F$ is $16 c m^{2}$ and BC = 2.1 cm. Find the length of EF. [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Marks

We have ,

$Δ A B C \sim Δ D E F$

$\Rightarrow \frac{a r e a (Δ A B C)}{a r e a (Δ D E F)} = \frac{B C^{2}}{E F^{2}}$

$\Rightarrow \frac{9}{16} = \frac{(2.1)^{2}}{E F^{2}}$

$\Rightarrow \frac{3}{4} = \frac{2.1}{E F}$

$\Rightarrow E F = \frac{4 \times 2.1}{3} c m = 2.8 c m$

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If ΔABC∼ΔDEF such that area of ΔABC is 9 cm2 and the area of ΔDEF is 16 cm2 and BC = 2.1 cm. Find the length of EF. [2 MARKS]

Concept: 1 Mark Application: 1 Marks We have , ΔABC∼ΔDEF ⇒area (ΔABC)area (ΔDEF)=BC2EF2 ⇒916=(2.1)2EF2 ⇒34=2.1EF ⇒EF=4×2.13 cm=2.8 cm

If $Δ A B C \sim Δ D E F$ such that area of $Δ A B C$ is $9 c m^{2}$ and the area of $Δ D E F$ is $16 c m^{2}$ and BC = 2.1 cm. Find the length of EF. [2 MARKS]