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Question

If ΔABCΔDEF such that area of ΔABC is 9 cm2 and the area of ΔDEF is 16 cm2 and BC = 2.1 cm. Find the length of EF. [2 MARKS]


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Solution

Concept: 1 Mark
Application: 1 Marks

We have ,

ΔABCΔDEF

area (ΔABC)area (ΔDEF)=BC2EF2

916=(2.1)2EF2

34=2.1EF

EF=4×2.13 cm=2.8 cm


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