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Construction of Triangles: Right Angle Triangle When 1 Side and Hypotenuse Are Given

If Δ ABC ∼ Δ ...

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If Δ ABC ∼ Δ PQR, h1 and h2 are the heights of Δ ABC and Δ PQR, AB:PQ=3:5 and h2=12 cm, then the value of h1 is

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Δ A B C \sim Δ P Q R

h_{1}

h_{2}

are the heights of

Δ A B C

Δ P Q R

respectively AB : PQ = 3 : 5 and

h_{2} = 12 c m

, then the value of

h_{1}

△ A B C

h_{1}, h_{2}, h_{3}

r

, then the minimum value of

\frac{h_{1} + r}{h_{1} - r} + \frac{h_{2} + r}{h_{2} - r} + \frac{h_{3} + r}{h_{3} - r}

Δ A B C \sim Δ P Q R

\frac{A (Δ A B C)}{A (Δ P Q R)} = \frac{16}{9}

P Q = 18

B C = 12

A B

Q R

are respectively:

Δ

A B C

the sides opposite to angles

A, B, C

a, b, c

A B C

be a triangle with altitudes

h_{1}, h_{2}, h_{3}

r

\frac{h_{1} + r}{h_{1} - r} + \frac{h_{2} + r}{h_{2} - r} + \frac{h_{3} + r}{h_{3} - r}

Q. The vertical poles of heights

h_{1}, h_{2}

h_{3}

at the vertices A,B and C of a

△ A B C

α, β

γ

respectively at the circumcentre of the triangle,If

cot α, cot β

cot γ

h_{1}, h_{2}, h_{3}

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Construction of Triangles: Right Angle Triangle When 1 Side and Hypotenuse Are Given

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